Originally Posted by
vart
No, running sum mean you need to continue add numbers til 0 is entered
Output should be something like this
Code:
Enter Number: 10
Running sum: 10, enter next number: 5
Running sum: 15, enter next number: 1
Running sum: 16, enter next number: 3
Running sum: 18, enter next number: 0
Final sum 18, thank you for using our product.
is this ok?
Code:
#include<iostream>
using namespace std;
int main()
{
int num1,next_numbers,total;
cout<<"enter the number:\n";
cin>>num1;
cout<<"\nenter next number:\n";
cin>>next_numbers;
total=num1+next_numbers;
cout<<"sum is at:\n"<<total;
for(next_numbers;next_numbers!=0;)
{
cout<<"\nenter next number:\n";
cin>>next_numbers;
total=total+next_numbers;
cout<<"sum is at:\n"<<total;
}
}