Thread: why does printf behave differently in the following example

The following program prints this, which is what I want it to do:

1 1
1 1
1 1
1 1
1 1

Code:

#include <stdio.h>
#define MAX_TERMS 5

int ret_one(int);

int call_counter;

int main() 
{
  int i;

  for(i = 1; i <= MAX_TERMS; i++, call_counter = 0) {
	 printf("%d", ret_one(i));
	 printf("%4d\n", call_counter);
  }

  return 0;
}


int ret_one(int num) 
{
  call_counter++;
  
  return 1;
}

but when I use a single printf statement in the loop like this :

Code:

  for(i = 1; i <= MAX_TERMS; i++, call_counter = 0) {
	 printf("%d%4d\n", ret_one(i), call_counter);
  }

it prints this :

1 0
1 0
1 0
1 0
1 0

I don't know why call_counter is printed as 0, I watched it in the debugger and its value is 1 when it's passed as an argument to printf, but it still prints out as 0. I tell you, these little things...