Thread: A very interesting puzzle of "extern char *"

Here is the code:

file.h

Code:

char p[5] = "abcd";

A.cpp

Code:

extern char* p;
int main(){
  printf("%c",p[2]);
}

The result is a run-time error (memory access fault, I think)
Why is that?

When I correct the A.cpp as

Code:

extern char p[];
int main(){
  printf("%c",p[2]);
}

It does work .