Thread: somefunc(int& a = 4) -> default argument for ‘int& a’ has type ‘int’

You can't have a reference to a literal value, therefore having a default argument for a reference doesn't make much sense.

One thing you could do (I don't reccomend doing this because it involves global variables) is make your reference have a default variable to refer to

Code:

#include <iostream>

int default_arg = 10;
void foo(int& bar = default_arg)
{
    std::cout << bar << std::endl;
}

int main()
{
    int i = 5;
    foo(i);
    foo();
}

Or, you could just overload your functions (This is a much better solution)

Code:

#include <iostream>

void foo(int& bar)
{
    std::cout << bar << std::endl;
}

void foo()
{
    std::cout << 10 << std::endl;
}

int main()
{
    int i = 5;
    foo(i);
    foo();
}