Somebody had created a physics programme somewhere so I thought i would have a go and add in some other stuff. It is very long. If someone could show me if there is any way to make it shorter I would be pleased. I have put in comments:
Code:#include <iostream> #include <string> //included for the use of strings #include <cstdlib> //included for the use of system ("CLS") using namespace std; int main(int argc, char *argv[]) { float resistance1 = 0; //obviously create a float varibale, same down below float resistance2 = 0; float resistancet = 0; float voltage = 0; float current = 0; string type = ""; //create a string, a string is just a line so it can take any number of letters, but there is a limit string rtype = ""; string end = ""; do //start a do while loop { cout<<"Please enter the type of calculation (lower case): "; //obviously enters text, note that i didnt use endl so that the input is on the same line as the writing getline(cin,type); //gets the input from the string named type cout<<endl; //this is where the line ends if (type == "voltage") { //if the calculation type is voltage then the following code is executed cout<<"Please enter the total resistance (Ohms): "; //once again not that endl is not there cin>>resistance1; //obtains the input as resistance1 cout<<endl; cout<<"Please enter the circuit current (A): "; cin>>current; voltage = resistance1 * current; //once the current and resistance are set then it will multiply them together to give you the voltage cout<<endl; cout<<"The supply voltage = "<<voltage<<"V"<<endl; //shows the answer cin.get(); //waits for the user to press return, I think cout<<endl; cout<<"Would you like to continue? (yes / no): "; getline(cin,end); //gets the input whether the user wants to end, when the input is yes the do/while loop repeats when no it ends. system("CLS"); //clears the screen incase the programme is repeating } else if (type == "current") { //else if the calculation required is current then do the following cout<<"Please enter the voltage supply (V): "; cin>>voltage; cout<<endl; cout<<"Please enter the total resistance (Ohms): "; cin>>resistance1; current = voltage / resistance1; //divides voltage by resistance to get the current cout<<endl; cout<<"The circuit current = "<<current<<"A"<<endl; //gives the answer cin.get(); cout<<endl; cout<<"Would you like to continue? (yes / no): "; getline(cin,end); system("CLS"); //clear the screen incase the programme is repeating } else if (type == "resistance") { cout<<"How Would you like to work this out? (series, parallel or v=ir): "; //asks you how you would like to calculate resistance getline(cin,rtype); //this is where the rtype string is used cout<<endl; if (rtype == "series") { //nested if staement...if you want to do it by series then do the following cout<<"NB, This Calculator can only take two resistances"<<endl; //this line of text does not take input cout<<endl; cout<<"Please enter the value of resistor 1 (Ohms): "; cin>>resistance1; cout<<endl; cout<<"Please enter the value resistor 2 (Ohms): "; cin>>resistance2; resistancet = resistance1 + resistance2; //adds the two resistances together for series circuits cout<<endl; cout<<"The total resistance = "<<resistancet<<" Ohms"<<endl; //gives the answer cin.get(); cout<<endl; cout<<"Would you like to continue? (yes / no): "; getline(cin,end); system("CLS"); //clears screen } else if (rtype == "parallel") { //nested else if statement, just the same as if, if you want parallel resistances then do the following cout<<"NB, This Calculator can only take two resistances"<<endl; cout<<endl; cout<<"Please enter the value of resistor 1 (Ohms): "; cin>>resistance1; cout<<endl; cout<<"Please enter the value resistor 2 (Ohms): "; cin>>resistance2; resistancet = (resistance1 * resistance2) / (resistance1 + resistance2); //more complicated sum, note brackets because divide is more important than + and * cout<<endl; cout<<"The total resistance = "<<resistancet<<" Ohms"<<endl; //gives the answer to the sum cin.get(); cout<<endl; cout<<"Would you like to continue? (yes / no): "; //asks the user if they would like to continue getline(cin,end); //gets the input to string end system("CLS"); //clears screen } else if (rtype == "v=ir") { //I think it is probablyobvious what this piece of code does cout<<"Please enter the supply voltage (V): "; cin>>voltage; cout<<endl; cout<<"Please enter the circuit current (A) : "; cin>>current; resistancet = voltage / current; cout<<endl; cout<<"The total resistance = "<<resistancet<<" Ohms"<<endl; cin.get(); cout<<endl; cout<<"Would you like to continue? (yes / no): "; getline(cin,end); system("CLS"); } else { //basically if the type of resistance calcultion is entered wrong then it will do the following cout<<"Sorry this calculator cannot do that!"<<endl; //another no input line cout<<endl; cout<<"Would you like to continue? (yes / no): "; //asks the user if they want to end getline(cin,end); //gets the string end system("CLS"); //clears screen } } //ends all the resistance code else { //as above just incase the calculation input is wrong, ie ie you type fgakjk instead of voltage cout<<"Sorry this calculator cannot do that!"<<endl; cout<<endl; cout<<"Would you like to continue? (yes / no): "; getline(cin,end); system("CLS"); } } while (end == "yes"); //end of the do/while loop, as long as the end string is equal tio yes then the programme will stay open return 0; } //ends the entire programme
