I have some of the code written down already, but I just don't know how I am going to display one line. I know how to use rand srand, and open a file, but I don't know how to cout just one line.
I am really confused as to what to do. I've tried Google, but I don't know what I'm searching for so I'm getting horrible results.
The code I have is:
This is my first program in awhile, so don't hate me for the syntax and, probably, numerous errors. Also, sorry for the indenting; it looks good in vi.Code:#include <iostream> #include <fstream> #include <cstblib> #include <conio.h> #include <ctime> using namespace std; int var(); int defu(); int main() { int choice; cout << "1. Open a variable file" << endl << "2. Open the default file" << endl << "Enter your choice: "; cin >> choice; switch ( choice ) { case 1: { var(); break; } case 2: { defu(); break; } default: { cout << "Invalid choice!" << endl << "Program closing..."; break; } } getch(); return 0; } var() { // initialize variables srand ( ( unsigned ) time ( 0 ) ); string filename; int line-n, yn, d; int x = 0; // prompt user for file cout << "Enter the name of the file you wish to open:" << endl; getline ( cin, filename ); // check to see if string is empty if ( filename.empty() ) { cout << "ERROR: No file name entered!" << endl; return 0; } // if string isn't empty else { // open file inp.open ( filename.c_str() ); if ( !infile ) { cout << "ERROR: Unable to open file" << endl; return 0; } else { // perform the line counting while ( !infile.eof() ) { x++; line-n = x; } // finaly, pick out a line and display it while ( yn != 1 ) { d = ( rand() %line-n ) +1; // this is where I don't know what to do if ( d ==