Thread: strcopy for an array

no the way u've done it, it should be newstring[i] = '\0';

but personally this is the way i would do it.

since '\0' character value is 0, the loop will end with that value.

Code:

for(i = 0; array[i]; ++i)
    newstring[i] = array[i]

newstring[i] = '\0';

actually i missed something in ur code above, it shouldn't be

Code:

char *newstring = new char[strlen(array)];

it should be

Code:

char *newstring = new char[strlen(array)+1];

requires the +1 for the '\0' terminator