Thread: Hows (my) code progressing, good?

I made all of the code below and learned everything in that code only in today's time, and didn't know any of it yesterday, am I doing better than most?

The code below works:

Code:

// My c++ Legend
/* Contains
all */


#include <iostream>


using namespace std;


int main()
{
    cout << "Enter a number: ";
    int x;
    cin >> x;
    cout << "You entered " << x << endl;
    if (x > 10)
    {
        cout << x << " is greater than 10" << endl;
        cout << x << " is a big number" << endl;
        if (x > 20)
        {
            cout << x << " is greater than 20" << endl;
        }
        else
        {
            cout << x << " is less than 20" << endl;
        }
    }
    else if (x < 10)
    {
        cout << x << " is less than 10" << endl;
    }
    else
    {
        cout << x << " is exactly 10" << endl;
    }
    return 0;
}

Also, if I create a new project "to be" my holy grail AI lol, should it be a Console Application?

Hodor is confused

All 3 of my question posts above are obvious, also I was recently talking to some of the members~

If they're ignoring me then maybe I should go some place new that hasn't learned "oh, he's bad, oh ya" thought, it's the thought you gain and are just being ignorant to me and from being productive.

It is interesting!

All "int"s should be start/create integer for my_name. Put a BIG START above main when it starrrrrrttsssss. Me doing very good see see!!

Originally Posted by ADVANCESSSS

All "int"s should be start/create integer for my_name. Put a BIG START above main when it starrrrrrttsssss. Me doing very good see see!!

If I may give a correction. Where a program starts is technically called the entry point.

The entry point for C++ is actually rather complex since it can be before main() is called. Global objects like std::cout are initialized first, if you #include <iostream>. This is usually minor, but when you create your own object in global scope, it will be important to know when it is created.

Additionally:

Code:

start integer for main()

I would not write this. The first line inside of main(), located after the opening curly brace, is actually where main() starts.

The int part in int main() is actually declarative. It only means that main will return an integer on completion: by convention, this value is 0 on success, and something else on failure.

Your AI will most likely not be just a console program. Console programs are for hosted environments like your computer. For your AI, you or someone will have to embed the program(s) onto the chips of the hardware for the robot, after the software is written and tested.

Basically, you need to target the robot's architecture.

If your AI doesn't have a body to interact with, then it's hard to say what kind of project it is.

But walk before you run. For now, it is okay to learn C++ with console applications on your computer.

Yes that's why those are above main, they are done in sequence, but then you start at main and gobil gobil around following it all lol~

But declaring int creates a storage binary integer dude, assigned to x or main.

Yes I actually have to add that 0 at the end is the success only for ThE ending.

Ok ok ok, so, what I'm doing first is coding my AI right, in only 1 Console Application right, then because it generates guesses this means it can be placed from Console Application to " " without corruption I hope and go into any robot and send the outputs to its servos right? Oh o, to test my AI I must put it innnn a robot....my c++ code doesn't need to be all formatted different does it!!?

Originally Posted by ADVANCESSSS

But declaring int creates a storage binary integer dude, assigned to x or main.

No, this is important. Function definitions give type names like int a different meaning. Just because you see an "int" before the function name, that doesn't mean that an int has been created. It simply tells you that an integer will be returned from the function.

If you use the function in a variable definition, then you've got the int.

Here, this might teach you the difference.

Code:

#include <iostream>
#include <typeinfo>
using namespace std;

int dbl (int value ) {
  return value *= 2;
}
int main() {
   // prove dbl() function works:
   int result = dbl(4463);
   cout << "dbl() result = " << result << endl;

   // prove dbl is not an int:
   cout << "type of dbl() is " << typeid(dbl).name() << endl;
   return 0;
}

dbl clearly works, but it isn't an integer. You get a mangled function name instead.

Ok ok ok, so, what I'm doing first is coding my AI right, in only 1 Console Application right, then because it generates guesses this means it can be placed from Console Application to " " without corruption I hope and go into any robot and send the outputs to its servos right? Oh o, to test my AI I must put it innnn a robot....my c++ code doesn't need to be all formatted different does it!!?

Well, embedded programming is different from programming C++ for the computer because of the hardware. Smaller machines tend to have less memory, so they probably won't load all of the standard libraries.

Again, instead of worrying about that you need to learn how to program in general. Every bit of hardware is different and it matters very much what you decide to use.

Wha........the whole code you wrote worked the way I said - all of the ints made placeholders that went along through the code, all else worked as I know how it works, and dbl was just the name the whole time, then you outputed the name simply plus put typeid (dbl) .name() which doesn't kill anything I was proving either.

So if I made the AI code, will I have to change it to go into hardware? Tell me what what what... Also I need to know if you can tell me how it's put in the robot and how do I get the camera's cout, I'm gonna face this and I gotta know....

Originally Posted by ADVANCESSSS

Wha........the whole code you wrote worked the way I said -

But you originally said "But declaring int creates a storage binary integer dude, assigned to x or main". Assigning something to main would mean that "main" would appear on the left side of an assignment statement. But that's not how you use main, or any other function.

all of the ints made placeholders that went along through the code, all else worked as I know how it works, and dbl was just the name the whole time, then you outputed the name simply plus put typeid (dbl) .name() which doesn't kill anything I was proving either.

All I set out to prove was that writing "int main()" where the function is define does not declare an int for storage. Everything up til now gave me the impression that you believed the opposite. That you actually understood the whole time is brand new information.

So if I made the AI code, will I have to change it to go into hardware? Tell me what what what... Also I need to know if you can tell me how it's put in the robot and how do I get the camera's cout, I'm gonna face this and I gotta know....

I don't have enough information to help you right now.