Thread: How can a binary get its working dir at run-time?

Originally Posted by meili100

Thanks, but

Code:

/proc/self/exe -> /home/me/myproject/bin/myprog

is a link.
How to get the

Code:

/home/me/myproject/bin/myprog

You could always parse ls -l or something . . . .

. . . or, if you can convince "open" or whatever not to follow symbolic links, you could just read the file directly.

Originally Posted by meili100

Thanks, but

Code:

/proc/self/exe -> /home/me/myproject/bin/myprog

is a link.
How to get the

Code:

/home/me/myproject/bin/myprog

Ok, so you probably need to use opendir()/readdir()/closedir() to open/read/close the directory entry then. Unfortunately, you won't be able to spawn a process and use something like a "ls | awk ..." or "ls | sed ...", since you would then get the path to "ls", rather than your application, which I assume is what you are actually after [although I suppose the stuff is also in a numbered process /proc/<pid>/exe (or similar) directory, so I suppose that would be possible to use for such scripting tricks].

Edit: Note that you would have to do (pseudo-code)

Code:

x = opendir("\proc\self");
while(readdir(dirinfo))
{
   if (dirinfo.fname == "exe") 
   {
      getlinkcontent();
      break;
   }
}
closedir(x);

--
Mats