Good evening,
I want to convert an amount of money e.g. 245.98$ to a string like two hundred and fourty five dollars and ninety eighty cents.
Could you please paste me a link where i can find an algorithm for this in order to be helped ?
Thanks, in advance!
search previous posts....not too long ago (maybe 2-3 weeks). Dave_Sinkula I believe it was, wrote and posted a link to this exact problem.
Well a bit difficult to find it...
it shouldn't be hard for you to write your own anyways
what determines the amount of hundres you have?
what determines the amount of 10's of dollars you have?
... single dollares you have?
... cents you have?
algorithm
hundreds = determine hundreds
tens = determine tens
singles = determine singles
cents = determine cents
output you have "hundreds" hundred "tens""singles" dollars and "cents" cents
theres your algorithm
Hint: if you divide the number by, say, one hundred using integer math, it will give you the hundreds digit.
Well i did that for the hundreds digit, but i don't know how am i supposedto take the decimal part?e.g. 123.88 ?
how am i supposed to take 88?
Multiply by, say, 10, and then use the above method.
Hi,
if the user types 123.88 i multiply it with 100 in order to take 12388 and then divide the number by ten in order to take every digit.
What if the user types 4 or 45,then my program is going to multiply them again with 100 and i'm going to have 400 , 4500
What shall i do then?
I do:
What shall i do ?Code:#include <stdio.h> #include <stdlib.h> int main() { float d; int cnt = 1; //counts the number of digits the number has scanf("%f",&d); d= d* 100; //multiply it by 100 cause the user can input a number with two decimal digits int k = (d / 10); while( k != 0 ) { cnt = (cnt + 1); k = (k / 10); } }
> d= d* 100;
1 to 19 you pretty much do as a switch/case because it's pretty irregular, but 20 upwards has a very definite pattern if you write out some examples using lots of /10 and %10 operations.Code:numToWords( d / 100 ); printf(" dollars" ); if ( d % 100 != 0 ) { printf( ", and " ); numToWords( d % 100 ); printf( " cents.\n" ); } else { printf(".\n" ); }
The only really tricky bit is working out where to start (is it hundreds or thousands), but even that works itself out with a bit of extra effort.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Convert it to a string and check for the presence of the '.' character. If yes, do the decimal thing, if no, don't.
Is this a function like strcpy or shall i write it myself?
My main problem is that i want to divide the number e.g. 123.88 into two integers 123 and 88.
cause the % has to be used between two integers
You can use modf() to do that.
System: Debian Sid and FreeBSD 7.0. Both with GCC 4.3.
Useful resources:
comp.lang.c FAQ | C++ FQA Lite
Could you please send me the implementation of this modf?If of course you can find it somewhere
