Thread: Random guessing game

I'm trying to program a simple game where the user has to guess a number between 1 and 1000. The game works for the most part, however it always displays the "You are correct! Play again? (y or n)" message twice. I don't understand why. Could someone here take a look at my code and point me in the right direction? I'd greatly appreciate it. The game is supposed to start over again, with a new random number if the user wins and presses 'y' - it's supposed to end if the user wins and presses 'n'.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main(){

int i = 1;
int ran = 0;
int input = 0;
char cont = 0;

srand( time( NULL ) );
ran = 1 + ( rand() % 999);



printf( "I have a number between 1 and 1000.\nCan you guess my number?\nPlease type your first guess.\n");
		
		
	while( i != 0){
		scanf( "%d", &input);
		if( input != ran ){
			if( input > ran)
				printf("You're too high. Try again.\n");
			if( input < ran)
				printf("You're too low. Try again.\n");
		}
		if(input == ran){
			printf("You're correct! Play again? (y or n)\n");
			scanf("%c", &cont);
			if( cont == 'y'){
				cont = 0;
				printf( "I have a number between 1 and 1000.\nCan you guess my number?\nPlease type your first guess.\n");
			}
			if( cont == 'n'){
				printf("Ending game.\n");
				i = 0;
			}
		}




	}

	return 0;
}