Thread: Never encounter such coding

Hi all,

i have never encounter a code that is written this way. From my experience, isn't a code is suppose to end when ; is encounter? So why is the following code has a \ after ; . can someone explain to me what the following code means?

Code:

#define a   (b |= ~c); \          //What is \ after ;
            (d |= e); \
            (f &= ~g); \
            (h |= i);

Thanks