Passing pointer to character to function

[alexpos]

My code has the following:

- a function with the prototype: "void mat_out(double a[][10], int m, int n, char * title);"
-within my main function i have "mat_out(inv, m, n, "Inverse");"
-within my actual function, i have "printf("%c", &(*title));". But my title does not show up!! Why?

[quzah]

Well aside from the whole "can't pass multi-dimensional arrays" problem, %c does not print a string. It prints one character, assuming you were actually doing that right, which you aren't. You're printing the address of the character pointer you're dereferencing, which is just the same as if you hadn't done anything at all.

If you want a string, it's:

printf("%s", title );

If you want a single character, it's:

printf("%c", *title );

Quzah.