Thread: problem of add two fractions

hi thanx for reply

i did add this line printf("The sum is %d", sum);

i forgot to post it


it displayed what i dont suppose

help

yea thanx

but i want the result like 1/3+2/7 =13/21

i want the result is 13/21

Then simply have 2 sum values, one for the numerator and one for the denominator like so:

Code:

sum_nom=((nump1*denom2)+(nump2*denom1));
sum_denom=(denom1*denom2);

And then use printf() like so:

Code:

printf("Sum is: %d/%d\n",sum_nom,sum_denom);

Code:

#include<iostream.h>
#include<math.h>
struct fractions
{
	 float a,b,c,d,e,f;
};

float sum (float u,float v);
int GCD(int a, int b);
int main (void)
{
 fractions f1;
 cout<<"Enter Integer value of numerator of first fraction= ";
 cin>>f1.a;
 cout<<"Enter Integer value of dinominator of first fraction= ";
 cin>>f1.b;
 cout<<"Hence first fraction= "<<f1.a<<"/"<<f1.b<< endl;
 cout<<"Enter Integer value of numerator of second fraction= ";
 cin>>f1.d;
 cout<<"Enter Integer value of dinominator of second fraction= ";
 cin>>f1.e;
 cout<<"Hence second fraction= "<<f1.d<<"/"<<f1.e<< endl;
 f1. c = f1.a/f1.b;
 f1. f = f1.d/f1.e;
 float result=sum(f1.c,f1.f);
 int i=result*pow(10,3);
 int j=pow(10,3);
 int k=GCD(i,j);
 i=i/k;
 j=j/k;
 cout<<f1.a<<"/"<<f1.b<<" + "<<f1.d<<"/"<<f1.e<<" = "<<i<<"/"<<j<<endl;

 return 0;
 }
 float sum (float u,float v)
 {
	 float w;
	 w=u+v;
    return w;
 }
 int GCD(int a, int b)
{
	 while( 1 )
	 {
		  a = a % b;
		if( a == 0 )
			return b;
		b = b % a;

		  if( b == 0 )
			return a;
	 }
}

this also add two fractions but not for all fractions. plz tell me what is the problem..........