Thread: passing arguments to functions

In my book I've read this:
"Data can only be added in
double word units. That is, one can not push a single byte on the stack."

So, I made a little experiment watching how arguments are passed to a function:
Consider this simple C program:

Code:

#include <stdio.h>

void func(int);

int main(void)
{  
	func(1);
}

void func(int a)
{
	int b=2;
}

Using disassembly in .Net I was abe to see this (among other things):

Code:

func(1);
00411BFE  push        1    
00411C00  call        @ILT+1405(_func) (411582h) 
00411C05  add         esp,4

So it is true! It is obvious that value of argument in this case 1 has been pushed on the stack!

Then I modified func and with the following code:

Code:

#include <stdio.h>

void func(double);

int main(void)
{  
	func(1);
}

void func(double a)
{
	int b=2;
}

I saw this:

Code:

func(1);
00411BFE  push        3FF00000h 
00411C03  push        0    
00411C05  call        @ILT+1405(_func) (411582h) 
00411C0A  add         esp,8

Instruction add esp,8 cleaning stack, 8 indicates 8 bytes for data type double. But what is unclear is those first two lines:
00411BFE push 3FF00000h
00411C03 push 0

How can I conclude from this that value of 1 is pushed on the stack?
I think that little endian notation is used so I try to calculate number taking 0xF03F, but that is number 61503 far away from 1.
All that assembler code was in main function, and I expected so because default calling convention that is used is --cdecl
Thanks for help!