Please show me

**lala** · 10-23-2002

This is a slightly more difficult problem. Alter your program from question 2 so that it deals with months as well as years, and produces output such as the following:
Enter the current year then press RETURN.
1996
Enter the current month (a number from 1 to 12).
10
Enter your current age in years.
36
Enter the month in which you were born (a number from 1 to 12).
5
Enter the year for which you wish to know your age.
2001
Enter the month in this year.
6
Your age in 6/2001: 41 years and 1 month.
The program should cope with singulars and plurals properly in the output, e.g. "1 month" but "2 months".

This is my program but i will leave a blank there because i don really know how to show the output for 1 month and 2 months

#include<stdio.h>
main()
{
int a,b,c,d,i,x,y,z,month,total;
printf("Enter current year then press RETURN : ");
scanf("%d",&x);
printf("Enter the current month (a number from 1 to 12) : ");
scanf("%d",&a);
printf("Enter your current age in years : ");
scanf("%d",&y);
printf("Enter the month in which you were born (a number from 1 to 12) : ");
scanf("%d",&b);
printf("Enter the year for which you wish to know your age : ");
scanf("%d",&z);
printf("Enter the month in this year : ");
scanf("%d",&c);

i=z-x;
total=i+y;
???????? <== here
???????
printf("Your age in %d/%d : %d years and %d month",c,z,total,month);
return 0;
}

And please tell me the way to make this programe as simple( i mean short)

**Shadow** · 10-23-2002

I would recommend, first of all, better variable names.

a,b,c,d,e would get confusing to me after awhile.
Just a tip.

**char** · 10-23-2002

First of all, have you designed any algorithm for calculating the age?

**ronin** · 10-23-2002

The algorithm part isn't for me, but this might help offer an idea of how to cope with month vs months.

Code:

#include<stdio.h>

int main(void)
{
	char *months[2] = { "Month", "Months" };
	int monthResult;
	
	printf("Enter a month (1-12): ");
	scanf("%d", &monthResult);
	
	if(monthResult == 1)
		printf("That's %d - %s right?", monthResult, months[0]);
	else if(monthResult < 1 || monthResult > 12)
		printf("Can't follow directions can you?");
	else
		printf("That's %d - %s right?", monthResult, months[1]);


	return 0;
}

**lala** · 10-23-2002

But i failed to combine it, and how to do convert it into function??

**ronin** · 10-23-2002

Just test the value that you got for your final month. If it's less than 2 use the first element of the array. As for a function, simply pass both the final values for the year and the month into the function.

Code:

void printValues(int, int);

int main(void)
{
  code to calculate results.
  ..
  
  printValues(month, year);
  ..

  return 0;
}

void printValues(int month, int year)
{
  char *message[3] = { " month old.", " months old.", "Invalid values detected." };

  if(month > 0 && month < 2)
    printf("%d years %s", year, message[0]);
  else if(month >= 2 && month <= 12)
    printf("%d years %s", year, message[1]);
  else
    printf("%s", message[2]);
}

Not perfect, but hopefully it will get you what you need.

Good luck.

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