hello guys,
here is my problem
main()
{
char st[]="hello";
char str[]="hai";
if (st==str)
printf("bye");
else
printf("byebye");
}
here in the comparison in the if loop either the entire strings will be compared r the first character
please expalin me
bye
srinu
srinu
>here in the comparison in the if loop either the entire strings will be compared r the first character
1.) if is not a loop, it's a construct.
2.) Neither the 'entire string' nor the 'first character' will be compared. You are only comparing the addresses where each of the strings(st[], str[]) are stored, and not the contents at those locations. Use 'strcmp()' instead.
shaik786 is correct, you can't compare strings like that. You have to use a library function or compare each character by yourself. BTW, main() should return a value, it is of type int.
>main()
The correct way to define main with no arguments is
int main ( void )
>char str[]="hai";
Looks harmless, right? Unfortunately this could break your program since identifiers starting with "str" are reserved by the implementation for future updates.
>if (st==str)
This test will always return false regardless of what the values in the arrays are. Note that the name of an array is a pointer to it's first element, so what you are doing with this test is checking two pointers to see if they point to the same address. Since they don't the test fails. If you want to check the entire string for equality of values you have to either loop through each element and test them by character or use strcmp:
-PreludeCode:if ( strcmp ( st, astr ) == 0 ) printf ( "bye\n" ); else printf ( "byebye\n" );
My best code is written with the delete key.
