Thread: C Programming - Dice Toss Chart

Code:

#include <stdio.h>
#include <stdlib.h>

int main (void)
{
int die_roll = xx;

while (die_roll-- > 0)    
{
    // one line of code here perhaps?
}
return 0;    
}

60 rolls and 60 results? or 6 out of 60?

Code:

#include <stdio.h>
#include <time.h>
#include <stdlib.h>


int main(void)     //int argc, const char * argv[]) {
{

    int number = (rand() % 6) + 1;
    int rolls = 60;
    int tosses1 = 0;
    int tosses2 = 0;
    int tosses3 = 0;
    int tosses4 = 0;
    int tosses5 = 0;
    int tosses6 = 0;

    srand(60);

    while ( rolls-- > 0)
    {

    switch (number)
    {
        case 1:
            tosses1++;
            break;
        case 2:
            tosses2++;
            break;
        case 3:
            tosses3++;
            break;
        case 4:
            tosses4++;
            break;
        case 5:
            tosses5++;
            break;
        case 6:
            tosses6++;
            break;
    }
}

printf("Number  Frequency");
printf("\n  1        %i", tosses1);
printf("\n  2        %i", tosses2);
printf("\n  3        %i", tosses3);
printf("\n  4        %i", tosses4);
printf("\n  5        %i", tosses5);
printf("\n  6        %i\n", tosses6);

return 0;
}

your results

Code:

Number  Frequency
  1        0
  2        60
  3        0
  4        0
  5        0
  6        0

Look at where you're calling to get a ran num, then when it starts checking that (same) number.
this I think is closer to what it should look like.

Code:

Number  Frequency
  1        13
  2        7
  3        8
  4        10
  5        15
  6        7

60 rolls 60 results

Code:

#include <stdio.h>
#include <stdlib.h>


int main (void)
{
int die_roll = 60;

while (die_roll-- > 0)    
{
printf("%d : %d  %d \n",die_roll, rand()% 6 +1, rand() % 6 +1);
}
return 0;    
}

Originally Posted by hihellooo

It should be 60 rolls to generate 60 random numbers.

So when you add all the frequencies together in the output it should equal 60.

imposable to add all the rolls together to equal 60 using a 60 random numbers thing.
that makes an equation like this (X + Y)^60 = 60; something like that. where X and Y = 1...6 on a random basis.

if you go back and look again, it is set up to only roll a total times of 60, with each match of 1 thru 6 it adds it each time. you just need to move your
number = rand() % 6+1; to a point where is calls it each time to get that new roll to check it again, else it will always be the same number at start up.

what is the max number two die can total at one given toss of both die with the largest number of each die being 6?
better put:
1 .. 6 on one six sided die. What is the greatest number that can be achieved times 2?

Code:

int die_roll = 60;
int total = 0, die1 = 0, die2 = 0;
while (die_roll-- > 0)    
{
    die1 = rand()% 6 +1;
    die2 = rand() % 6 +1;
    printf("%d : %d  %d \n",die_roll, die1,die2 );
    total += (die1+die2);
    
}
printf("total : %d\n", total);

results of total 60 random rolls of two die 1 ... 6;

Code:

total : 399

can you post your original assignment verbatim?
results

Code:

userx@slackwhere:~/bin
$ ./frequency
0: 13
1: 12
2: 8
3: 13
4: 3
5: 11
----
Total frequency count: 60

the only thing I can see that MIGHT BE (don't quote me on that) wrong here is your rand a die has 1 - 6

Code:

  hist[rand() % 6]++;

what would happen if you wrote it like before?

Code:

  hist[rand() % 6 + 1]++;

to keep it between 1 thru 6.

I went back up and reread it again,
have to toss a die 60 times and then display a chart with the results that should look like this:
I was using a two die throught process.

but as far as this goes

have been stuck on this for about 2 days because nothing I've been doing works. Please help me understand this while using the while loop.

I think you got way past that issue.

I have not seen it coming up zeros either, so I'd give you an A and Saturday off.