Hello.
I am trying to copy the content of one string into an another. But it does not work. Why not? Here is the code:
Code:#include <stdio.h> #include <stdlib.h> #include <ctype.h> #include <string.h> int main(){ char *b[200][3]; char *left1[200]={""}; b[5][1] = "John"; strcpy(left1[5], b[5][1]); return 0; }
Last edited by nerio; 09-08-2017 at 02:16 AM.
Left1 doesn't have any allocated space you can write to.
Try
Left1 [200][10]
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Salem, a little off topic but I got a question:
Why is the code posted on here often so cryptic? Everyone uses one letter variable names, nondescriptive names, etc...
There are way too many bad instructors teaching C that do not advise their students to use descriptive names for functions and variables, with the exception of loop variables.Originally Posted by Asymptotic
