Thread: Need a quick check for this function call

Ok guys, I'm about to smash my computer. I am doing this function call the same way I have it in another program but it keeps tell me that when I try to call the function "a" is not indentified. Am I completly missing something?

Code:

#include <stdio.h>
#include <stdlib.h>
 
int initialize(int a[]);
int main()
{
 const int MAXSIZE = 20;
 int arr[20] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19};
 int selection = 0;
 int choice;

 printf("Please select an option\n");
 printf("    0 - initialize\n");
 printf("    1 - square\n");
 printf("    2 - halve\n");
 printf("    3 - accumulate\n");
 printf("    4 - transpose\n");
 printf("    5 - shift\n");
 printf("    6 - reverse\n");
 printf("    or anything other integer to exit\n");
 scanf("%d \n", &selection);
 if(selection == 0);
 {
 choice = initialize(a); //This is where it tell me a is not identified
 }
  
}
int initialize(int a[])
{
 
 
 int a [20] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19};
 int i = 0;
 
 printf("now the array is \n");
 for(i = 0; i <= 20; i++)
 {
  
  
  printf("%d", a[i]);
 }
 return 0;
}

I havent finished the if statement cause that "a not identified" is driving me crazy