Thread: Loop only printing zeros??

I am writing a program for my programming class and I have run into a problem. I got the entire program completed/compiled, but for the output, it's printing only zeros?

This is the HW problem:

1. A class of students received scores of 81.4, 75.3, 90.0, 96.9, and 85.6. Declare and initialize an array named “scores” to store these values. Write a loop to display the contents of scores. Make sure that your printout is readable with spaces or commas between each grade. For example:

The scores are: 81.4 75.3 90 96.9 85.6

And here is my program:

Code:

 
# include <stdio.h>

int main()
{
        double score[5];
        int i;

        score[0]= 81.4;
        score[1]= 75.3;
        score[2]= 90.0;
        score[3]= 96.9;
        score[4]= 85.6;

        printf( "The grades are:\n" );

        for (i=0; i < sizeof(score)/sizeof(*score); i++)
        {
                printf("%.1lf,", score[5]);
        }
        printf("\n");
        return 0;
}

Thank you in advance for any help!

quick guess; try "%.1f," instead of "%.1lf,", printf does not want/need the leading "l".

Code:

printf("%.1lf,", score[5]);

Tim S.

Ick, didn't work. This is the output I am getting:

The grades are:
0.0,0.0,0.0,0.0,0.0,

Thank you for your help!

ardavirus is on the right track. You declare your array to have 5 elements, but arrays in C start at 0, so you only have score[0], score[1], score[2], score[3] and score[4]. score[5] doesn't actually exist, so you're in undefined behavior. Try using your loop variable i as an index.

Yup, I got it! Thanks! It's working now!