Thread: User input being a number?

Well seeing as 6,4 is a string really...

Code:

char buffer[ BUFSIZ ];

fgets( buffer, sizeof buffer, stdin );

if ( sscanf( buffer, "%d,%d", &foo, &bar ) == 2 )
{
   printf( "%d\n", foo );
   printf( "%d\n", bar );
}

Thus I think foo and bar can be used now. Have you read our FAQ, which should help you on questions like this?

Oh thanks. Yeah I should have read the FAQ. Sorry about that.

Originally Posted by Watabou

Hi guys,
I have a technical question. How do I see if the user's input is a number?

So for example, when they type in 6,4 how can I get both 6 and 4 to store it in two variables?
I tried to implement this using a if statement like so : if(input == "%d%d") but I guess it doesn't work like that.

Help please?

You already have one good suggestion but you can also try...

Code:

int a = 0;
int b = 0;
int c = 0;

c = scanf(%d,%d",&a,&b);
if (c < 2 )
  puts("One of those was not a number");

All of this should be explained in your C library documentation. Most good compilers have relatively complete help files for just this reason.