Thread: Proper way to pass in 2d array to function?

You can't just make an empty-sized array:

Code:

void cannotdothis( type bad[][] );

You could fake it I suppose somehow, with a void pointer. Or you could just make it so you dynamically allocate it:

Code:

type **makearray( size_t x, size_t y ) {
    ...allocate space...
    return it;
}

Quzah.

Use the variable-length arrays for C99:

Code:

type func(int rows, int cols,type array[rows][cols])

or if you use dynamic array, then:

Code:

type func(type **array, int rows, int cols)

for the dynamic array, you can't pass in the static array, however.

Code:

void func( int ** array, int rows, int cols)

.
.
.
int arr[10][10] = { .....};
func(arr, 10,10) // would not work.