Thread: While loop issues

I need to write a program that randomly generates multiplication problems based on how many the user says they want. So far this is what i've got:

Code:

#include <stdio.h>
#include <time.h>

int main () {
	
	int number, initialnumber, first, second, guess, answer;

	//Seed random number
	srand(time(0));
	
	printf("How many problems do you want?\n");
	scanf("%d", &initialnumber);
	
	number = initialnumber;
	
	int start = time(0);
	while (number > 0) {
	
		//Create problem numbers
		first = 1 + rand()%12;
		second = 1 + rand()%12;
		answer = first * second;

		printf("Answer: %d x %d\n", first, second);
		scanf("%d", &guess);
		
		if (guess == answer)
			number --;
		else
			printf("Incorrect, try again.\nAnswer: %d x %d\n", first, second);
			number --;
		}
	int end = time(0);
	int timespent = end - start;
	printf("You completed %d problems in %d seconds.\n", initialnumber, timespent);

	return 0;
}

The problem I have is if they get it wrong it's supposed to display the same question again. I know that the else statement is completely useless as it doesn't even scan in their answer, I just put it there when I was brainstorming. How can I get it to check the new answer they've given instead of looping back around? Do I need to do something other than a while loop?

What you need is an inner loop where the exit condition is a correct answer...

Code:

	while (number > 0) {
	
		//Create problem numbers
		first = 1 + rand()%12;
		second = 1 + rand()%12;
		answer = first * second;
 do
     { 
		printf("Answer: %d x %d\n", first, second);
		scanf("%d", &guess);


		
		if (guess == answer)
			number --;
		else
			printf("Incorrect, try again.\nAnswer: %d x %d\n", first, second);
			number --;

}
while (guess != Answer) 
		}

Obviously this isn't the total solution, but it should give you some idea how to set it up.

Aha I got it! Thank you!

My pleasure.