Thread: Passing char ** (is losing reference)

Hi, I'm working on my second C program ever and I'm lost...

I have 2 source files. I'm passing a char ** from one function in one file to another function in a second file, it's losing the reference and pointing to garbage. Can some one tell me what I'm doing wrong ?

Here's some code

Code:

FILE1.C
int _tmain(int argc, _TCHAR* argv[])
{

	char ** input_word_list;

	/* THIS WORKS WELL */
                input_word_list = get_input_line();

	/* THIS WORKS FINE */
	int i=0;
	while ( (strcmp(input_word_list[i], EOW)) ){
		printf("----> %s\n",input_word_list[i++]);
	}
	
	get_db_con(input_word_list); 
return 0;
}
FILE2.c

int get_db_con(char ** input_word_list)
{

                /* THIS FAILS WHY ???? */
                int i=0;
	while ( (strcmp(input_word_list[i], EOW)) ){
		printf("FROM get_db_con ----> %s\n",input_word_list[i++]);
	}

return 0;
}

and here is the included header for each FILE1/2

#define EOW     "~"


int get_db_con(char **);
char ** get_input_line(void);

***********************************************

I used malloc in the first file in a local function, do I need to do somthing FAR etc.. ?? How do I ?
Is that why it's losing the data, cause it's out of scope, how do I scope it right ?


Thanks for the help,
-Areal

>> while ( (strcmp(input_word_list[i], EOW)) )

Unrelated to your problem - but you may as well make it clear what kind of comparison you expect to end the loop.

while ( strcmp(input_word_list[i], EOW) == 0 )

These two comparisons are not the same, in fact they make the loop behave completely the opposite from each other.


Quzah.