Thread: Numbers printed with characters

Hello, i have to make a program that would print out numbers represented with characters like this:

8317

Code:

+--+ +--+ + +--+
 !  !    ! !    !
 +--+ +--+ +    + 
 !  !    ! !    !
 +--+ +--+ +    !

srry i could get itto look any better, the first number is 8 and then 3 and so on...

So far i did this:

Code:

#include <stdio.h>

int main()
{
	char *deliStevilke[]={ // numbers representet with characters
		"+--+", // 0
			"+  +", // 1
			"!  !", // 2
			"   +", // 3
			"   !", // 4
			"!   ", // 5
			"+",	// 6
			"!",	// 7
	};
	
	int stevilke[10][5]={ // numbers how they are to be printed on the screen
		{0,2,1,2,0}, // 0
		{6,7,6,7,6}, // 1
		{0,4,0,5,0}, // 2
		{0,4,0,4,0}, // 3
		{1,2,0,4,3}, // 4
		{0,5,0,4,0}, // 5
		{0,5,0,2,0}, // 6
		{0,4,3,4,3}, // 7
		{0,2,0,2,0}, // 8
		{0,2,0,4,0}, // 9
	};
	
	int stevilo;
	
	scanf("%d", &stevilo);
	// print the number in character style
	printf("%s\n", deliStevilke[stevilke[stevilo][0]]);
	printf("%s\n", deliStevilke[stevilke[stevilo][1]]);
	printf("%s\n", deliStevilke[stevilke[stevilo][2]]);
	printf("%s\n", deliStevilke[stevilke[stevilo][3]]);
	printf("%s\n", deliStevilke[stevilke[stevilo][4]]);
	
	return 0;
}

I have no truble printing if you put in 1 number like 9. I dont know what to add so that i could print a number like 9999.

Could somebody give me some idea what to do?

Thank you.
bnk

take the no and use %10 operand to find out the digits at the unit place and then the answer in the same loop again and print this as a single digit.

take the no and use %10 operand to find out the digits at the unit place and then the answer in the same loop again and print this as a single digit.

Kepil, i understad how to use the %10 operand. If for example i do:

8713%10

the result is 3, but this is the last digit and i have to print this one at the last place. Just thinking if i print the 3 and then jump to the start of the line and then with the help of a loop calculate the next digit. But how do i substract the 3 from the number 8713 to get the next number 1 and so on?

foxman thank you for your help, but my knowledge is not so big in the way i could use the malloc function for the memory and you used so many pointers i kind of lost my way

You can use a combination of divide and mod to get the digit you want. Like:

Code:

#include <stdio.h>

int main()
{
    int num = 8713;
    int digit;
    while( num > 0 )
    { 
       digit = num % 10;
       num /= 10;
       printf("%i\n", digit);
    }
    getchar();
    return 0;
}

Mike thank you again for helping.

This is what i did:

Code:

#include <stdio.h>

	char *deliStevilke[]={ // numbers representet with characters
		"+--+", // 0
		"+  +", // 1
		"!  !", // 2
		"   +", // 3
		"   !", // 4
		"!   ", // 5
		"+",	// 6
		"!",	// 7
	};
	
	int stevilke[10][5]={ // numbers how they are to be printed on the screen
		{0,2,1,2,0}, // 0
		{6,7,6,7,6}, // 1
		{0,4,0,5,0}, // 2
		{0,4,0,4,0}, // 3
		{1,2,0,4,3}, // 4
		{0,5,0,4,0}, // 5
		{0,5,0,2,0}, // 6
		{0,4,3,4,3}, // 7
		{0,2,0,2,0}, // 8
		{0,2,0,4,0}, // 9
	};

int main()
{

	
	int stevilo,i=0,k=0,j=0;
	int pomoznoPolje[10];
	
	
	
	scanf("%d", &stevilo);
	

	while(stevilo>0)
	{
		pomoznoPolje[i]=stevilo%10;
		stevilo/=10;
		i++;
	}
	k=i;
		
	for(j;j<i;j++)
	{
	printf("%s\n", deliStevilke[stevilke[pomoznoPolje[k-1]][0]]);
	printf("%s\n", deliStevilke[stevilke[pomoznoPolje[k-1]][1]]);
	printf("%s\n", deliStevilke[stevilke[pomoznoPolje[k-1]][2]]);
	printf("%s\n", deliStevilke[stevilke[pomoznoPolje[k-1]][3]]);
	printf("%s\n", deliStevilke[stevilke[pomoznoPolje[k-1]][4]]);
	k--;
	}
	return 0;
}

And this is what comes out:
Now i just have to print this in a horizontal line not vertical. Is there any way to do that?

Code:

8743
+--+
!  !
+--+
!  !
+--+
+--+
   !
   +
   !
   +
+  +
!  !
+--+
   !
   +
+--+
   !
+--+
   !
+--+

Here's a better solution.. I wrote this a while ago, I believe, it explains the concept so you can adapt it to your own program.

Code:

#include <stdio.h>
#include <string.h>

int main(int argc, char **argv)
{
     char array[9][10][20] = 
     {
          {" ### ","    "," ### "," ### ","     "," ### "," ### "," ### "," ### "," ### "},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"#   #","   #","    #","    #","#   #","#    ","#    ","    #","#   #","#   #"},
          {"     ","    "," ### "," ### "," ### "," ### "," ### ","     "," ### "," ### "},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {"#   #","   #","#    ","    #","    #","    #","#   #","    #","#   #","    #"},
          {" ### ","    "," ### "," ### ","     "," ### "," ### ","     "," ### "," ### "},    
     }, 
     *nr = argv[1];
     unsigned int i = 0, h = 0;
     
     for( i = 0; i < 9; i++)
     {
          for(h = 0; h < strlen(nr); h++)
               if(nr[h] !=  ' ')
                    printf(" %s ", array[i][nr[h] - 0x30]);
               
          putchar('\n');
               
     }
     
     
     return 0;
          
}

Thank you all, it finally worked.

Some of the print outs, i even used the "special" character type:

Code:

0123456789
 ┌──┐ ┐ ┌──┐ ┌──┐ ┬    ┌──  ┌──┐ ┌──┐ ┌──┐ ┌──┐
 │  │ │    │    │ │    │    │       │ │  │ │  │
 │  │ │ ┌──┘  ──┤ └─┼  └──┐ ├──┐    ┼ ├──┤ └──┤
 │  │ │ │       │   │     │ │  │    │ │  │    │
 └──┘ ┴ └──  └──┘   ┴  ───┘ └──┘    ┴ └──┘  ──┘

Code:

1008887
 ┐ ┌──┐ ┌──┐ ┌──┐ ┌──┐ ┌──┐ ┌──┐
 │ │  │ │  │ │  │ │  │ │  │    │
 │ │  │ │  │ ├──┤ ├──┤ ├──┤    ┼
 │ │  │ │  │ │  │ │  │ │  │    │
 ┴ └──┘ └──┘ └──┘ └──┘ └──┘    ┴

Code:

26101976
 ┌──┐ ┌──┐ ┐ ┌──┐ ┐ ┌──┐ ┌──┐ ┌──┐
    │ │    │ │  │ │ │  │    │ │
 ┌──┘ ├──┐ │ │  │ │ └──┤    ┼ ├──┐
 │    │  │ │ │  │ │    │    │ │  │
 └──  └──┘ ┴ └──┘ ┴  ──┘    ┴ └──┘