Thread: 6 digit number

Code:

/* 
Write a program that inputs a six-digit number, separates the number into its 
individual digits, multiple each separated digits by 2 and prints the digits 
separated from one another by three spaces each. (Hint: use the integers 
divisions and modulus operator.) For example, if the user types in 42339 the
program should print 8 4 6 6 6 18 
*/

Can some one give me some more hints in how to solve this program. What iam thinking is once the user enters an integer 245246 read each number as a character and then times it by 2. But the question is what should i do? Thanks for your help and guidance.

% and /

Quzah.

>Can some one give me some more hints in how to solve this program.

Code:

1) Prompt user to input number
2) Read number into an int or long
3) Use a loop to separate and print each digit
   a) Use modulus operator to extract digit
   b) Use division operator to update number for next modulus
   c) Print digit * 2

The above will print the digits in reverse order, so if the digits must be printed in the order entered, you'll need to use an array to reverse them, or a recursive function instead of a loop.

Thanks for the explanantion and the tips.

This is how my program looks now but now i want the numbers to be multiply by 2. Each digit should be multiply by two, example if enter 423339 the output should be 8 4 6 6 6 18

Thanks
[tag]

Code:

#include <stdio.h>

int main()
{
	int num;
	
	printf("Enter a six-digit number:");
	scanf("%d", &num);
   	
	printf("%3d",num/100000);num=num/100000;num=num%100000;
	printf("%3d",num/10000); num=num%10000;
	printf("%3d",num/1000);  num=num%1000;
	printf("%3d",num/100);   num=num%100;
	printf("%3d",num/10);    num=num%10;
	printf("%3d",num/1);
	printf("   \n");
	num=num%1;
		return 0;
}

[/tag]

Hint: you don't want to divide the number by anything after each printf(), because if you do, some digits will be lost.

Sorry guys for asking that question. I figure it out, thanks for your help i only needed to put the * 2 where it was it was needed to be place. When i ask the question i was not thinking properly. I check the same problem in 2 hours time and i saw the simple mistake. It was so funny

later and thanks

Good god, guy. There's a thread just below yours that asked the same question. Crazy. You guys in the same class or something ?

Basically this problem is very simple, but you have to think about how to getting the numbers. Iam asking the user for a 6 digit number so i divide by 100,00 and then get the remainder of %100,000 of the same digit and then continue with the same logic until i reach the number / 1 and then %1.
The logic is that the number is / and then %. This is all the program is doing you have to know how the % (remainder) works and thats it.

My advice is to get a piece of paper and work it out how the program is getting solve and eventually you will get the picture. Is just some basic calculations. I have commented the code to help you... Hope it helps you.

Code:

#include <stdio.h>

int main()
{
	int num;
	
	printf("Enter a six-digit number:");
	scanf("%d", &num);
   	
	printf("%3d",num/100000);num=num%100000; // 6 digit number is divided by 100,000 and then optain remainder %100,000 
	printf("%3d",num/10000); num=num%10000;  // 5 digit is divide by 10,000 obtain remainder %10,000
	printf("%3d",num/1000);  num=num%1000;   // 4 digit is divided by 1000 obtain remainder %1000
	printf("%3d",num/100);   num=num%100;    // 3 digit is divide by 100   %1000
	printf("%3d",num/10);    num=num%10;     // 2 digit is divide by 10    %100
	printf("%3d",num/1);     num=num%1;      // 1 digit is divide by 1     %1 same logic  
	printf("   \n");
		return 0;
}

Originally Posted by redx2evil

happy_reaper do u know how to do it?..cheers

Yes, I do. Something similar was even answered in the other thread.

Code:

printf("%3d",num/1);     num=num%1;

I wonder it compiles. My program crashed when I used modulus with 1.
Your num is always 0 when you use modulus with 1.