Thread: float returns invalid value!!

Hi!
I have a very stupid question, but I don't understand why it doesn't work!

Code:

int x=360, y=100;
fload d;
..
d = (x/y);
printf("%f\n", d); // d returns 3.00000, but it should 3.60000

Where did I go wrong? Thank you!

Code:

 d = (x/y);

instead of try this

Code:

 d = (float)(x/y);

Thanks! That worked!!

Originally Posted by q6z4k

Thanks! That worked!!

Are you shure ?

the result of

Code:

(x/y);

is an int. You want it to be a float so you have to either cast x or y to a float.

Code:

d = ((float)x/y);

should work
Kurt

remember

1. int / int ---> int
2. int / float ---> float
3. float / float ---> float
4. double / double ---> double


so u could have dont something like this as well

Code:

#include<stdio.h>

int main()
{
    int x=360;
    float y=100.0;
    
    printf("%f",x/y);
    getchar();
    return 0;
}
/*my ouput
3.600000
*/

ssharish2005