Thread: Basic debugging question

I was given the following program and asked to debug it but I am having an issue understanding some of the code in it. First of all I can't seem to find out what the const char ** means. Secondly, in the final printf statement it appears that the %s string is not printing when the program is runned. Can anyone point in the right direction with this one?

Code:

     #include <stdio.h>
     #define DOCTORATE 1
     #define CHOICE 2
     const char *a[2][3] =
         {
         {"Hitler", "Stalin", "Bin Laden"},
         {"Clinton", "Bush", "Powell" }
         };
     int main()
         {
         const char **array;
     #if D0CT0RATE
         array = a[1];
     #else
         array = a[0];
     #endif
         printf( "An honorary doctorate award "
           " is issued to %s\n",
           array[CHOICE] );
         }

const char** is for constant pointer to a pointer which is of type char data, means that you cannot change values of array a, and btw %s is printing fine...

"When the program is runned."

Seriously?

We're really making authors and wordsmiths of the English language, roll over in their graves, tonight!