Is this correct

[jack_2205]

#include <stdio.h>
int main()
{
int c=10, d=20;
void swap(int *c, int *d);
void change(int *c, int *d);

printf("Before swap c=%d , d=%d ,", c,d);
swap(&c,&d);
printf("After swap c=%d , d=%d ,", c,d);
}

void swap(int *c, int *d)
{
change(&c,d);
}

void change(int *c, int *d)
{
int t;
t=**c;
**c=*d;
*d=t;
}

I am getting a compilation error

kan1usp4.c:19: warning: type mismatch with previous implicit declaration
kan1usp4.c:15: warning: previous implicit declaration of `change'
kan1usp4.c:19: warning: `change' was previously implicitly declared to return `
nt'
kan1usp4.c: In function `change':
kan1usp4.c:21: invalid type argument of `unary *'
kan1usp4.c:22: invalid type argument of `unary *'

On the face of it the program looks fine. But, then why is the compilation error.

Thanks..Jack.

[jack_2205]

U r correct. Thanks for ur reply.

Thanks..Jack

[knave]

#include "stdio.h"

void swap(int *a, int *b)
{
	int temp;

	// swap the values
	temp = *a;
	*a =   *b;
	*b = temp;
}

int main()
{
	int x = 5, k = 10, temp;

	printf("\n Before swap() : 'x' = %d , and 'k' = %d", x, k);
	swap(&x, &k); // Swap the values of variables 'x', and 'k'
	printf("\n After  swap() : 'x' = %d, and 'k' = %d", x, k);

	return 0;
}

Try not to use something like -> int **c, just use one * ( *c) ...