(array+ 1 ) and (&array+1) diff ?

[Alexpo]

Hi,

name of array gives us the base address always.
so, in the code below:

int arr[]={1,2,3};
printf("%p:%p", arr+1,&arr+1);

we should get out put as

22220104: 22220104 (if the base address is 22220100).
But why it is 22220104:22220112.

Thanks and regards,
A

[tabstop]

Adding one to a pointer advances that pointer by the size of the thing pointed to.

arr points to an int, so it advances 4 (sizeof int on your system).

&arr points, not to an int, but to an int[3]. The size of an int[3] is 12, so twelve bytes are added.