Variable Type issue

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Originally Posted by Elysia

Just pass %f, and it will print any available decimals.
Beware that floating points in somewhat inaccurate, so 1/8 can also return 0.12500001 or something. Don't know if it can happen to this particular equation, but it can happen to certain ones.

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Bad example. 1/8 == 1/2^3 => exact floating point number (0.125) - unless your hardware is broken...

0.1 or 0.7 are values I know are NOT representable in floating point.

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Mats

I know, I didn't think of that, but I think the point was that a division with 1 and 8 would in real life give 0.125. So if done "correctly" in C/C++, it should be 0.125 too (and not 0.12500001).

Thx everyone for help...

Just for record I solved it by putting into the calculator a slide-bar by which a user selects how many decimals does he want... Useful because it automatically rounds up decimals

I use _snprintf() as it is safer and less likely to crash your app than sprintf()