I have a program that diplays a popup menu when you right-click the tray icon. The menu works perfectly fine except that it if you activate the menu and dont click a menu item it will stay up.
Help pleaseCode:case WM_SHELLNOTIFY: { if(lParam == WM_RBUTTONDOWN) { GetCursorPos(&pt); TrackPopupMenu(hPopupMenu,TPM_RIGHTALIGN,pt.x,pt.y,0,hwnd,0); } if(lParam == WM_LBUTTONDBLCLK) { SendMessage(hwnd,WM_COMMAND,SHOW,0); } } break;
thanks
Hmmmmmmm,
I do this and don't have that problem, then I use a local for the menu so may just be loosing scope.
try..........
Adding TPM_RETURNCMD to the TrackPopupMenu style. Catch the return (0 for fail or ID selected).
Then kill/hide the menu if zero returned.
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You need to set your window as foreground with SetForegroundWindow() before calling TrackPopupMenu().
Quoted from TrackPopupMenu on MSDN:
To display a context menu for a notification icon, the current window must be the foreground window before the application calls TrackPopupMenu or TrackPopupMenuEx. Otherwise, the menu will not disappear when the user clicks outside of the menu or the window that created the menu (if it is visible). However, when the current window is the foreground window, the second time this menu is displayed, it displays and then immediately disappears. To correct this, you must force a task switch to the application that called TrackPopupMenu at some time in the near future.
thanx guys.
hdood's solution worked perfectly
