Thread: A small problem with TextOut()

Hi, I have this string "line1\nline2\nline3\n", that I would like to print out with TextOut(), but since TextOut() doesn't support '\n', I had to make it myself.
And It does print "line1" and under it "line2", but that's it, why?
Where is "line3"?

"line1\nline2\nline3\n" is been passed inside msg

Code:

void preview_text(HDC hDC, int x, int y, char *msg)
 {
   int i, j=0;
   char line[100]={0}; 

   for (i=0; i<strlen(msg); ++i)
    {
      if (msg[i]=='\n')
       {
         TextOut(hDC, x, y, line, strlen(line));
         memset(line, '\0', 100);
         y += 13;
         j = 0;
       }
      else
        line[j++] = msg[i];
    }
 }

Thanks.

Thanks, I will check that out... But still what's wrong with this code? It suppost to work right.

code:-----------------------------------------------------------------------------

void preview_text(HDC hDC, int x, int y, char *msg)
{
int i, j=0;
char line[100]={0};

for (i=0; i<strlen(msg); ++i)
{
if (msg[i]=='\n')
{
TextOut(hDC, x, y, line, strlen(line));
memset(line, '\0', 100);
y += 13;
j = 0;
}
else
line[j++] = msg[i];
}
}
--------------------------------------------------------------------------------

Your code is looking perfect. Pls check the strings's entirety at the place from where you are calling this function.

I mean whether this function get "line1\nline2\nline3\n" or "line1\nline2\nline3" ?

the input!!! of course... it only calls for TextOut() when it sees '\n'...

Thanks.