okay...im kind of confused...
i am sitting here at work, kind of bored. I have finished all my work, so I decided to program for awhile just for fun.
But anyways, as most of us know, in a big endian machine, the most significant byte is stored lower in memory, so the integer FFFF would be stored as such in memory:
00 00 FF FF
In a little endian machine, the least significant byte is store lower in memory, and so that same number would be stored as such:
FF FF 00 00
Well, my machine here at work is a Win2k machine...running on an Intel processor, and therefore it is little endian because Intel processors are little endian. Or at least according to this website they are: http://www.netrino.com/Publications/...ndianness.html
Well, what confuses me is this. I outputted the unsigned integer FFFF bit by bit from left to right, and it came out like this:
00000000 00000000 11111111 11111111
All i did was bitshift and output in a loop. Well, since intel machines little endian, isnt that backwards? shouldnt it be outputting:
11111111 11111111 00000000 00000000
or am i just not thinking straight right now.....
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maybe this should have gone on the tech board...i dunno...i just posted it here...but if it should be on the tech board feel free to move it there
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