how and where is int_bottom invoked?

[john_12]

Hello,

I am following along a tutorial on operating systems and do not understand where in the code the "int_bottom" routine is invoked (it is written in interrupstubs.s).
Can someone tell me how/where it is invoked? Thanks!

this is the tutorial, the code is written first in commit number 5:
Files for part 5, https://www.youtube.com/watch?v=AgeX-U4dKSs * AlgorithMan-de/wyoos@01557ac * GitHub

you can go to commit number 5 by cloning this repository and executing
git checkout 01557ac3b68bc7f9e39e76d4b4bf2fdbe627ce3d to reset to commit number 5.

[Salem]

They're assembler macros.

.macro HandleException num
.global _ZN16InterruptManager19HandleException\num\()Ev
_ZN16InterruptManager19HandleException\num\()Ev:
    movb $\num, (interruptnumber)
    jmp int_bottom
.endm

Which then gets invoked by the assembler to generate a whole bunch of interrupt handlers.

HandleException 0x00
HandleException 0x01
HandleException 0x02
HandleException 0x03
// etc etc

[john_12]

thanks for your reply. This I understood but I mean the "int_bottom" routine as I wrote. Nowhere in the code do I see a jump to "int_bottom". I know that a hardware interrupt writes the interrupt vector onto the pci and then the cpu is switched into interrupt mode. It somehow fetches the interrupt vector from the pci but then where is the piece of code that sets the instruction pointer to "int_bottom"?

[Salem]

What do you think 'jmp int_bottom' does?

[john_12]

oh wow ouch... thank you!