1. ## virtual page question

An other, question how do I figure how many bits are needed for an offset, how many physical page and how many virtual pages. again using 8 bit addressing. 64 bits phyical memory and a page size is 16 bytes.

This what I think I have.

5 bits for the offet.

for the virtual page, 2^8= 256, then 256/16 for 16 virtual pages

Physical pages are 7.

Am I right or totally wrong?

2. 64 bits phyical memory
That's definitely wrong.

3. Originally Posted by CornedBee
That's definitely wrong.
the 64 bits of physical memory was given by my professor. He knows that it is not realistic.

4. Originally Posted by uscuba2
64 bits phyical memory and a page size is 16 bytes.
16 bytes = 128 bits = twice as much memory as you've got.

5. Perhaps it's meant to be 64 BYTES?

--
Mats

6. Uh, are we sure the instructor doesn't mean a 64-bit address space? In other words a memory size of 2^64?

64 bits is 8 bytes. Yet a page size of 16 bytes? That's nonsense. I have to believe he meant 2^64 bytes, not 64 bits.