Thread: I don't know if this is the right board to ask

  1. #1
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    I don't know if this is the right board to ask

    Is there any condition when the following code might fail and/or crash?

    Code:
    $ more filter.pl
    #!/usr/bin/perl
    
    my $cont = 0;
    while ($line = <STDIN>) {
        if ($line =~ /^ /) {
            next if $cont;
        }
        $cont = 0;
            
        foreach $i (@ARGV) {
            if ($line =~ /^$i:/) {
                $cont = 1;
            }
        }
        if (!$cont) { print $line; }
    }

  2. #2
    Malum in se abachler's Avatar
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    yeah, if you try to compile it as a C/C++ file it will fial, since it isnt C/C++, you should try a perl board for help on that code.

  3. #3
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    Quote Originally Posted by abachler View Post
    yeah, if you try to compile it as a C/C++ file it will fial, since it isnt C/C++, you should try a perl board for help on that code.
    Maybe you should learn how to read. And I quote

    Tech Board (5 Viewing)
    Computer questions not related to C/C++/C# programming

  4. #4
    Hail to the king, baby. Akkernight's Avatar
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    Well, I guess the board description kinda fails there a bit xP
    But it's meant for technical questions, most in the line of hardware I'd say... But Cprogramming.com is more made for the C languages, except for C# I think...
    Currently research OpenGL

  5. #5
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    Most of the requests for a Java board have been referred to the use of the Tech board, IIRC. I don't see a problem with a Perl question here - a lot of C programmers know Perl too. If he's already an active member, he might as well utilize the community.

    It's been a long time since I was familiar with Perl, but considering that the only statements inside your loops are simple assignments and explicit conditionals, I think it's a safe bet your code wont fail or crash.

  6. #6
    Devil's Advocate SlyMaelstrom's Avatar
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    I agree, looks pretty safe. Unless you or the user can find a way to harm your <STDIN> handle from outside of the program, then I don't see anything that could halt this unexpectedly.
    Sent from my iPadŽ

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