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  1. Thread: 1=0.

    by tabstop
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    6,418

    So if f(x) -> inf and g(x) -> 0, then f(x) * g(x)...

    So if f(x) -> inf and g(x) -> 0, then f(x) * g(x) would represent inf * 0. So if f(x) = x, and g(x) = 1/x as x gets large, then f(x) is always 1. If f(x) = x^2 and g(x) = 1/x as x gets large, then...
  2. Thread: 1=0.

    by tabstop
    Replies
    61
    Views
    6,418

    And since when did canceling in multiplication...

    And since when did canceling in multiplication give zero?
  3. Thread: 1=0.

    by tabstop
    Replies
    61
    Views
    6,418

    Because infinity * 0 = infinity / (1/0) =...

    Because infinity * 0 = infinity / (1/0) = infinity / infinity, which I think we already did.
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