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can someone explain to me why I don't get an output running the following code:

#include <stdio.h>/* count characters in input; 2nd version */
main()
{
double nc;
for (nc = 0;...

I changed it to pointer and it worked.
text itself is a pointer so why can't I use it?
when writing --> text = text+1; I'm changing the memory address that text contains, I'm causing it to point...

why can't I run this?

char text[]="nave"; char *pointer=text;
if(*text='n'){


printf(" \n the string equal to: %s",pointer);
*text='m';...

thanks for your replies

why does it result in undefined behavior?

is it possible to run this code?

#include <stdio.h>

int main(void) {

char *my_string="Hello";
printf("%s",my_string);
*my_string='w';
printf("%c",my_string);

Okay, thanks

there's something that I dont understand
how can you print a string using a pointer? what is the logic standing behind it?
like for example in the following code:

#include <stdio.h>


int...

when running the following code, why do I get two different memory addresses?

#include <stdio.h>


int main(void){


int short signed number=-3;
int short signed *pointer=&number;

Thanks for the explanation

Hi,
I'm learning C programming language at the moment.

Just out of curiosity what happens if the place holder and the argument is not compatible?
for example if I write: printf("some text %d,...