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I have written the following.


#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>

int main(void) {
int i, pid;
pid = fork();

just forget the last post. i used "new" and member pointers and now it works smooothly.

int main ()
{
list<Member *> mlist;
Member memtest;
Employee emptest;
int ans;
string buf;

cout << "What do you want to put?" << endl
<< "Member (1) - Employee (2) ? : ";

#include <iostream>
#include <string>
#include <list>
using namespace std;

class Member {
string name;
public:
Member(string name) {
this->name = name;

In a class i have many string (#include <string>) variables. In the destructor do i have to do anything special for the string? i tried delete name_of_string and the compiler complains that delete...

letdef struct list_tag * list;

struct list_tag {
enum {
.....
} kind;
struct {
int x;
struct {
int y;

i m working with six header files and six source files, thats why i couldn't post it all. I was hoping for a short easy answer. it must be a scope thing which i can't sort out.

first of all it is a valid struct Type_tag object. secondly i put the ... in the next line and i get the error on the line where the (symbolentry->type) is

typedef struct Type_tag * Type;

struct Type_tag {
enum {
TYPE_unit,
TYPE_bool,
TYPE_char,
TYPE_int, ...

I have the following declarations:



typedef struct SymbolEntry_tag * SymbolEntry;

struct SymbolEntry_tag {
Identifier id;
Scope scope;
...

or you can use if


if (x < 0)
x = -x;

or


x = (x > 0)? x : (-x);

If you type tab the compiler will see the ascii character 9. that's how he can distinguish between the two.

ok i got it. I was thinking of a tab as many spaces. But printf doesn't print many spaces, it moves to the next tab stop. So i was thinking that printf makes a mistake when it prints a single...

i used gdb to debug.



Hardware access (read/write) watchpoint 3: yytext

Value = 0x93c70 "'\t'"
0x00003c38 in main () at lexin.c:107
107 printf( "token = %d, lexeme =...

i m using flex to write the lexical analyser and i have the following prob:
this code


//other stuff for flex

int main ()
{
int token;

ok, i know about the escape sequences \n \t \r etc. But i m asking: considering that newline is a single character is the following acceptable?


char c = '
';

the reason i m asking is because...

i didn't catch your post itsme86. It is probably the devc++ editor's fault. is the newline considered a single character?


c = '
';

thanks for the replys. i tried the same code (the one i posted) in cygwin (gcc) and the output was :
"a a" (a [tab] a). can anyone explain why this difference?

#include <stdio.h>

int main()
{
char c = ' '; /* I typed tab here */
printf("a%ca\n", c);
return 0;
}

thanks everyone. itsme86 the function is exactly the same for the two types and using long for both long and char inputs works just fine.

Can you have a function that has an argument that could be either one type or another. For example foo(x input) where x is either char or long int? should i look into enums?

I guess someone has heard of the programs that when executed print their code like this one :


#include <stdio.h>

main()
{
char*p="main(){char*p=%c%s%c;printf(p,34,p,34,10);}%c";
...

I'm trying to install gtk for devc++. I have downloaded two files gtk-runtime.exe and gtk-dev.zip. Could someone tell me what to do with those files? Documentation hasn't helped me, i tried several...

#include <conio.h>

int getch();

FAQ

is there a way to read input from the keyboard while the user enters it. before he presses return.