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Ah ok, I get your point. I think I should just use memcpy when I exactly know the lengths and if I am sure that I don't have some case like your example.. Thanks

This is such an simple idea but I would have never thought about it! I will write one myself, thank you!

EDIT:


Ok, that is also what I thought. But I read somewhere I should avoid using...

of course I meant here:


string[length + con_len] = '\0';

I wonder if I am using the string operations properly. So If i have a char array, and I want to copy another one into it, what I do is :



char *example = "Example_string";
int length =...

Thank you for your patience *jackass, and yes I have 64 bits.

@anduril

I only want to save the addresses, so I will also try your suggestion with the fprintfs. Thank you

Still not working well:




char *exa = "0x1017bcee0";

int **all_str = malloc(sizeof(char*)*100), **b = all_str;

*all_str ++= exa;

Hmm your solution is not working for me, I just tried:




char *my_example = "0x1017cbee0";

int **all_str = malloc(sizeof(char*)*100), **b == all_strs;

*all_str++= my_example;

Yes like is said in the second answer, pointers to ints, and then later I want to retrieve those pointers

I don't see how this is casting my string, it is just saving it to a list? Oh but i thing it is my fault, I forgot to mention I have to save it in a list of pointers to ints, so int *my_list

I am wondering if it is possible that I cast a char array to a pointer. What I mean is I generate a text file containining pointers to some addresses, since I want to save memory, so I have something...

And what if I want to do it the other direction, is an (int) enough?
Wow this is a really nice method. thank you a lot. I also managed to cast a address to a char:



int lala = 0;

...

Undefined symbols for architecture x86_64:
"_itoa", referenced from:
_main in main.o
ld: symbol(s) not found for architecture x86_64

But sprintf does it for me. thank you really...

Is it possible to get the string representation of an int. So I mean if i have:

5, I want to get '5'.

I was searching in the internet and I found this solution:




int number = 5;

Hmm ok, I thought to use sort since it has a good worst case runtime, and stuff like bubble sort is quadratic so I don't know which one is my sorting algorithm i should use :S

Nobody has any suggestions :??

Hello!

I already posted one question related to my quick sort problem, but since it is solved and I have a new one, I am starting a new thread. So I try to sort an array with qsort and then save...

Yes well I removed the error by just introducing a separate function for swap:



void switch_pos(int *one, int *two) {


int temp = *one;
*one = *two;
*two = temp;

Oh yes and the do's in my first post are just typos!line 20, 21

#include <stdio.h>
#include <stdlib.h>
#include <dirent.h>
#include <string.h>

int main(int argc, char** argv) {


int tot = 10; int ini;
int*list;

So I try to sort an array with qsort and then save the new order, so this means if I have a list like:

4 3 7 2
[0] [1] [2] [3],

after sorting it becomes:

2 3 4 7
[3] [1]...

I was wondering if it is possible to check if two addresses, so pointers are equal.

I was saving the address of an array, and later wanted to identify it by the address, so if my area has the...

OK i think I got your point, I will try to change the method.

The error I got was just an index mistake I made.. But I have more question, I run valgrind over my code, and its complaining...

Ok, but don't I need one more array to save the new calculated values? or how do you mean it, to use two pointers, like I understood it: one for my current array, and another one in the new one where...

Ok, I have again a problem, and this time i will try to make a post acceptable for the readers :).

So what I want to do: my method gets a list of structures:



#define BOOL unsigned int...

But yes, maybe you are right, i Should split it into several small methods and test step by step. So I go back to work..thanks