What is the difference between a pointer in C and a reference in Java? Well, a pointer in C is a 4 byte allocation that points to an address in virtual memory. Maybe this isn't the right question for...
Type: Posts; User: johnmerlino
What is the difference between a pointer in C and a reference in Java? Well, a pointer in C is a 4 byte allocation that points to an address in virtual memory. Maybe this isn't the right question for...
I am learning C and Java simultaneously and the Java docs state the following:
"Inthe Java programming language, a multidimensional array is an arraywhose components are themselves arrays. This is...
I created a basic socket server, which listensing for incoming udp data. When I run the netcat program, I get a response:
$ nc -luv 1732
Connection from 10.50.11.12 port 1732 [udp/*] accepted...
In the below function:
double atof(char s[])
{
double val, power;
int i, sign;
for (i = 0; isspace(s[i]); i++) /* skip white space */
;
But if n is a negative value, n will always be less than 1 and therefore the loop will never execute, if what you say is correct, no?
The below function confuses me. Basically, since unsigned integers use a two's complement system, we cannot take the inverse of n before processing it, should n be negative. Because the largest...
The example exercise in the C Programming language book states the following:
Write the function itob(n,s,b) that converts the integer n into a base b character representation in the string s . In...
I know the difference between insertion sort and shell sort. Insertion sort compares every single item with all the rest elements of the list, whereas shell sort uses a gap to compare items far apart...
so then this must be done at compile time
Below is an extracted portion of an example exercise from the C Programming Language book:
void escape(char * s, char * t) {
int i, j;
i = j = 0;
while ( t[i] ) {
...
printf doesn't support format specifier for clock_t?
I am looking at a piece of code from an exercise in the C Programming Language. It uses the clock_t data type for one of its variables. And then later when it prints the data of the variable, it does...
Yeah I removed dynamic memory allocation and used array instead and I get same results but without memory leaks. The lesson is avoid dynamic memory at all costs, except when reading from serial...
Thus, while I can free *sensors, I cannot free **sensors, which is the pointer to pointer.
Since sensors is a pointer to a pointer, the i-th index of sensors points to *temp which points to the allocated memory on RAM. Hence, I can free that memory using the following:
void...
This is result of valgrind:
==17724== Memcheck, a memory error detector
==17724== Copyright (C) 2002-2013, and GNU GPL'd, by Julian Seward et al.
==17724== Using Valgrind-3.9.0 and LibVEX;...
I wrote this program:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct sensor {
unsigned long long int address;
I can have at most 3 structs in array, but it could be 0,1,2 or 3 structs in array. I am trying to avoid dynamic memory allocation. I initialize sensors to 3 to reserve space for them in memory,...
NULL doesn't work either, so it appears you cannot set 0 and NULL as values of array of structs, because if you want to check if the current index of array is NULL, there is no way to check since it...
In the below code, when I compare a struct to 0, it gives me the error "error: invalid operands to binary != (have ‘struct <anonymous>’ and ‘int’)". The problem is I will have an array of structs and...
THe following:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char *argv[])
{
This program works as expected:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct {
unsigned long long int address;
float ...
I have this simple program below:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct {
unsigned long long int address;
float ...
I have this simple program:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
static unsigned char cmd[]={
0x01,0x80,0x00,0x00,0x00
This function below takes a pointer as an argument. What I expect to happen is, since expr++ has higher precedence than *expr, that is, the primary expression operators have higher precedence than...