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yes.

From 6.5.4.2


Looking up the forward reference


In this case, the casting you suggested seems necessary.

It seems to change the pointer to point to a location one byte away from the previous location, it doesn't seem to be normal pointer incrementation.

Please read the webpage


Representing a pointer is not the same as being a pointer.

If plah is a pointer you can assign values to it, why don't you try doing something like



int...

If she reads in characters from a stream till she gets an EOF. I don't see any problem whatsoever.
[added later]
My bad, the function has to take in a string.

It is easy to get floating point random numbers from rand() .


#include <stdio.h>
#include <stdlib.h>

int
main(void)
{
unsigned int seed=123;

lcc isn't that bad a compiler. The probability of your being wrong is greater than lcc being broken.

No, plah is an array.
sizeof plah = 5*sizeof(int) which in all probability will be larger than sizeof(int *)
try this out


#include <stdio.h>

int
main(void)
{

Put it in a do while loop


#include <stdio.h>
#include <ctype.h>

int main (void) {

char response;

Interesting.
http://www.network-theory.co.uk/articles/boundschecking.html

Is there anything wrong in the code to allocate arrays of a particular length below. I have never returned pointer to arrays before so I wanted to be sure.



#include <stdio.h>
#include...

fgetc() returns an int, EOF is usually an int value that cannot be represented as a char, so you might end up with an infinite loop unless you declare ch as a int.

Try


printf("%d",*p_map);

They are also a part of trigraphs, some special sequences of three characters (most probably you won't ever need to use trigraphs)...

Your code original code worked?

Comparing a pointer to NULL and comparing a pointer to zero are equivalent,
so, if fp is a FILE * , then
if(fp==0) and if(fp==NULL) are testing the same thing

if(fp) (which is equivalent to...

To explain what I have done is
I calculate C(n+1,r+1) from C(n,r) using the formula

C(n+1,r+1)= (n+1)*C(n,r)/(r+1)

I break up C(n,r)=q(r+1)+rem
where

0<=rem<=r

Even C(68,34)=28453041475240576740
is greater than 18446744073709551615 = ULLONG_MAX
by a factor of 1.5

The largest C(2n,n) that fits into a unsigned long long is C(66,33)
Assuming usigned...

Dude, what is the sizeof(unsigned long long) on your system,
C(70,35)= 112186277816662845432
ULLONG_MAX= 18446744073709551615 (on my system) :confused:
C(70,35) > ULLONG_MAX :confused:

For my code its (64,32) so you are squeezing five more bionomial sequences.
Not bad!!! Good work!!!

Thantos,
What is the smallest value of C(2n,n) for which your method fails?

thanks! That explains it.

sizeof's are coming to be 8.

I did cast the results to unsigned long long in an attempt to make it work, it didn't help.

.file "junk.c"
.def ___main; .scl 2; .type 32; .endef
.text
LC0:
.ascii "c=%llu b=%llu\12\0"
.align 2
.globl _main
.def _main; .scl 2; .type 32; .endef
_main:
pushl %ebp