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laserlight
I dont want to use arrays in my program, I want alternative way.

i is a range of number from 1 to 10 and rem is remainder of entered digit. if statement compares whether i is equal to rem or not if i is equal to rem then count is incremented.

Yes, I understand but instead of using count array can I use count variable and use it in a loop?

I am storing the input in integer variable.

The challange is not to use arrays. Use modulo and division operation to calculate.

I am writing a program in which user enter any value and the program calculates the occurence of any digit in a number. For example, if user enter 4323122 the output should like this

3 is present...

I have modified my code by using compound termination condition


#include<stdio.h>
int main(void)
{
int a,b,i;
for(i=1; i<=4; i++)
{
for(a=0; a<=0 ; ++a)

#include<stdio.h>
int main(void)
{
int a,b,i;
for(i=1; i<=4; i++)
{
for(a=0; a<=0 ; ++a)
{
printf("%d",a);

ok i tried for 2 variables but i am getting another problem of printing alternate 0's and 1's :/

Yeah ok I will try. :)

Yeah it is mandatory to use 6 nested loop.

I have to use 6 nested loops.

I am having problem in choosing termination conditions for each nested for() loop.

use 6 nested loops to generate the output & my code is incomplete right now. I am not getting how to proceed further.

ok got it :)

#include<stdio.h>
int main(void)
{
int a,b,c,d,e,f,i;
for(i=1; i<=64; i++)
{
for(a=0; a<=0; ++a)
{
printf("%d",a);

The output Should be like this:
11931

it is mandatory to use nested for() loop. I am not allowed to use any decimal to binary conversion.

What are index variables?

Matticus



#include<stdio.h>int main(void)
{
int a,b,c,d,e,f,i;
for(i=1; i<=64; i++)
{
for(a=0; a<=0; ++a)

In short we have to print Truth Table of 6 bit binary digits as truth table covers all possible combinations.

i selected 6 variables for 6 bits and 1 variable to control outer loop which initializes with 1 and terminates at 64. This outer loop is to generate rows.

ok. variables should hold '0' & '1' as the program is for printing binary numbers. Possible combinations are 64 for 6 bit number. This means outer loop terminates at 64.

Adak... the object of this question is to generate truth table using nested for() loop.

i did a bit paper work. But didnt find any solution. I am facing problem in choosing termination condition for for() loop. I selected 6 variables for 6 bits.