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How should I use fgets() ?

Hello, I would like to make a function, void read_line(File *f, char line[]), that does taht :
It will read a line of a file (already opened) replacing the last \n by the char of the end of a string...

true that it is more logical this way...


#include <stdio.h>
#include <string.h>

int main (int argc, char*argv[]){
int i,j;
int length;
char *argx;

true that it works like that but then what is strcpy for ?


here is the final working program!


#include <stdio.h>
#include <string.h>

int main (int argc, char*argv[]){

oh right, sorry for the spelling as you can tell it is not my native language...

how can I use only argv[i] ? wont it make a two dimention table if I say argv[i][length] ?

thanks again for the...

Well I did that, and I am sure it is not what you expected me to do knowing that it doesn't work...

#include <stdio.h>
#include <string.h>

int main (int argc, char*argv[]){
int i;
...

Well maybe it will be easier to understand I I type the actual instructions...

We want to make a program called pointc2pointo that for any string taken as an argument, if it terminats by ".c",...

Hello,

I am creating a program named pointc2pointo wich will take a list of arguments and find the ones that terminates by .c and replace it by .o

so far I have that :

#include <stdio.h>
...

Thank you!

I don't really know what you mean by line by line but maybe you can look every char unetil you find \n .

It finaly works!

#include <stdio.h>
#include <string.h>

int main(int argc, char *argv[]) {
int i = 0;
if (argc > 1) {
printf("there are %d elements \n", argc);
...

So some of you might think it is funny or useless, but I am trying to practice and you can tell I need to...
so I want // to work as an enter, when the program sees // it prints \n, but I don't know...

je comprend...
du coup il suffit juste de rajouter des espaces dans tout ça et peut-être une code pour le retour à la ligne.
merci de votre aide :)

Well sorry for that I sometimes get confused...

argc is the number of arguments isn't it ?

argc is the number of argument isn't it ?

#include <stdio.h>


int main(int argc, char *argv[]) {
int i = 0;
if (argc > 1) {
printf("there are %d elements", argc);
printf("the first element is %s", argv[1]);...

So I changed it to that :

#include <stdio.h>

int main (int argc, char*argv[]) {
int i=0;
if (argc > 1) {
printf ("there are %d elements",argc);
printf ("the first...

oh I think I know

sorry I modified my post.

Well so I tryed to modify my program so that I create a file with all of the arguments and not only the first one, and once again it doesn't work. can you help me again pease ? :D


#include...

%s , s if for string right ?

Thank you, this tutorial will still be usefull. (stahta01)

oh right I am stupid... thanks a lot :D

Hello,

I would like to know where is my mistake on that program I made :


#include <stdio.h>

int main (int argc, char*argv[]) {

if (argc > 1) {

Oh ok I get it... I thought NULL would be error message, but I have to do it myself...