Search:

I'm trying to compile my program but am constantly getting the same error. on compiling the message is: "error: conflicting types for 'evaluate'"
"note: previous declaration of...

i've used:



for(i=0; i<MAX_ROWS; i++)
{
fscanf(input, "%f %f", &x[i], &fx[i]);
}

but it hasn't worked properly. Is there a reason for this?

Thanks a load!

So I've run into a problem that I need to solve.
I have a file that has two columns and I need to read this file, and put each column to a separate array. I've done the array sizing, and I've...

So I'm just having trouble with what c can actually do and how.
I've got a program which calls a function at some points to evaluate multiplication of values within different arrays. I have 3...

I've managed to fix it. I'd defined my matrix with dimensions i and j which meant it didn't have enough memory (i think). I've got it working now! Thanks anyway!

I get a seg fault when run!

So I'm trying to inport a file into an array. The file is of known size, containing 9 numbers (ie a 3x3 matrix) separated by spaces and new lines. I need to take this file, and turn it into an array....

I added the variable checking which worked fine for checking variables, but changed the output of my program. I used:


if(sscanf(argv[1], "%lf", &a) != 1 || sscanf(argv[2], "%lf", &a) != 1 ||...

I found my problem. I had a statement for finding the determinant before these if statements and of course the determinant was 0 if b and a or c were 0 so it was having problems. Fixed now! Thanks a...

The problem is I need certain clauses for if a and b = 0 and then a,b and c = 0 etc which would mean repeating myself multiple times in those 3 if statements.

Changed my code to:


else if(a == 0)
{
if(b == 0)
{
/* If a, b and c are 0, no equation */
if(c == 0)
{

There's an error message about "too few arguments to function 'sscanf' " when I try to compile. I'll leave it I think, but thanks for the attempts!

So using something like



if(sscanf(argv[1]) != 1)
{
exit(failure)
}

Ok thanks a lot! I'll work that into what I need. Thanks again!

Thanks, but where abouts do you mean? In the integrated if function (inside "if(a == 0)")?

I keep getting "Segmentation faults" whenever I try it. Currently using:



if(argc != 4)
{
printf("Please enter 3 variables after program name.\n");
exit(EXIT_FAILURE);
}
/* Check...

If I haven't scanned the values, how will it know what to test against?
To me seems like that would test the argv[x] values and then let the user change them to a letter and the program goes on...

So instead of using 'isalpha(a)' I'd have to use 'isalpha(argc[1])'?

Sorry, realised I didn't post the whole code. I already have a number of inputs check, I'm just interested now as to if they are numbers, and if not, showing an error message:



if(argc...

I'm afraid not. In the cases where some are 0, the function can still work.
For example, if only c is zero a result is still possible.

So by using something along the lines of:



else
{
sscanf(argv[1], "%lf", &a);
sscanf(argv[2], "%lf", &b);
sscanf(argv[3], "%lf", &c);
if(isalpha(a) || isalpha(b) || isalpha(c))

So I've written a program that works almost perfectly and the only thing it's missing is an input validation to stop letters being allowed as inputs. I'm not very sure what you would call doing this...

Sure. The bit including what i'm talking about:



if(DET < 0)
{
printf("The roots of this equation are imaginary!\n");
}
else if(DET == 0)
{

I tried using the if within an if, but it still won't work as required. I have:



else if(a == 0)
{
if(b == 0 && c != 0)
{}
else if(c ==0 && b != 0)
{}