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Thank you
I worked on some examples
I came to know that function overloading in c++ not depend on return type
only on parameters order, size & there type.

Is Function overloading depends on return type of an function in c++? explain me with example please

yes i got it
I as to declare it as static / dynamic
Thank you

please help me i trying to print array elements but it printing some junk values

#include<stdio.h>
#include<conio.h>
int *fun()
{
int i[]={1,2,3,4,5};
return &i[0];
}
void main()