Python.
I have found that with C, Python, and a little bit of shell scripting, I have no conceivable need for anything else.
Type: Posts; User: TheBigH
Python.
I have found that with C, Python, and a little bit of shell scripting, I have no conceivable need for anything else.
Actually, if you pass an integer to a function that expects a double, the integer gets automatically promoted to a double.
The problem with this program is that you're printing the address of...
Okay, let's say you want to check whether square #161 is on any border.
The row number is then 161 / 15 = 10 (remember that this is integer division, remainders get thrown away)
The column number...
Check out ncurses.
At the end of the while loop, you free(temp) and thereby make "present" point to freed memory. You should make present point to something that exists before the next iteration of the while loop.
So your problem is that there is a star at the end of the string, but you don't want it there?
Why not loop down to 2, and then print the last 1 outside the loop?
OK, what are you having trouble with?
Basically, each link in a linked list is a structure containing two things: the data you're storing, and a pointer to the next link in the list.
What have you tried? Show us your code.
Can you show your whole code? What errors are you getting?
Why does SIZE need to be an array in the first place?
In line 2 you probably want "int *size". You forgot the asterisk.
Q1) One way to approach this would be to make a new variable that counts how many of x,y,z are true.
Q2) C syntax does not allow things like
if( a < x < b) /* do stuff */
You need to...
Good. So if the number of the row (variable i) is equal to the number of the column (variable j) print a 5, otherwise print a @.
If I just hand out the code you won't learn anything, but the...
That's a good start, your code prints a square of @ symbols.
Inside your "j" loop you'll need an if statement that decides whether to print a @ or the digit.
If I'm in row 2, column 4, do I...
Your code does not even compile, because you don't declare many of the variables you're reading. I can also tell that, even if they were declared, you're not handling firstname and lastname right;...
Here's a neat little trick:
round_to_nearest_int( double x ) {
return floor( x + 0.5 );
}
Can you figure out for yourself why this works?
It's a subtle little bug. If the string contains an 'A' or an 'a', then keyword[j] gets set to zero. Once that happens, keyword[j] = 0 = '\0' = end of string. So strlen(keyword) thinks the string...
Do you even know what data type your fib variable is supposed to be? You declare it as a pointer to an integer, then you set it to an integer with the function "a", then you treat it as an array of...
Set b[0] and b[1] before your loop.
Also, in line 11, you're missing the opening square bracket in b[i-2].
Let me talk you through what is happening.
On the first iteration of the loop, it tests whether a[0]<a[1]. If that's true then "return 1" happens, which halts the "sorted" function with a return...
If you used the array directly, the final newline would be put into the array. This code looks like it is intended to avoid that.
Do you know beforehand how many words there are, and how long the longest word is? If so,
char Words[NUMBER_OF_WORDS][LENGTH_OF_LONGEST_WORD+1]; /*the +1 leaves room for the \0 that terminates...
Um, the problem is exactly what the error message says. You check the value of "input" in the while statement, but the scanf that assigns things to it happens after the first check.
Try this as...
Use == instead of = to test equality.
Yes, fgets.