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hilarius, so you mean two following two lines are the same, right?


char *p = "abc";
const char *p = "abc";

And, if you know C++, is it the reason that g++ will warn char *p = "abc" for p is...

If so, why can I when in gdb or use char p[] instead of char *p? What's the difference between them?

#include<stdio.h>
int main(){
char *p = "Abc";
*p = 'a';
printf("%s\n", p);
return 0;
}
It received SIGSEGV on the 3rd line. But if I use
char p[] = "Abc";, it goes well.
So why I...

Oh, I see. Thank you!

Hi there,

Here is what I've tried:


#include<stdio.h>

int main(){
char str[10];
int a;